Question 1018880
 
Question:
A binomial distribution is based on n = 15 trials and success probability p = 0 4. . What is the
probability that the binomial random variable equals its mean value?
 
Solution:
For the given binomial distribution with n=15, p=0.4, mean=μ=np=6.
P(k=6;15;0.4)={{{C(15,6)*0.4^6*(1-0.4)^(15-6)}}}
={{{5005*0.004096*0.010078}}}
=0.2066
 
Observation:
P(k=7)=0.1771 < P(k=6)
P(k=5)=0.1859 < P(k=6)