Question 1018797
8 ways to select one red.
6C2 ways to select 2 blue
that is 15.
numbering the blues 1 through 6
12
13
14
15
16
23
24
25
26
34
35
36
45
46
56
So the number of ways are 8*15=120
no more than two blue mean 15 ways for 2+6 ways for 1+the number of ways one can select 3 from 8 red (0 blue).  That is 8C3 or 56 ways, so the total is 15+6+56=77 ways.
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more blue than red.
3 blue and 0 red.  That is 6C3=20 ways. 6C3 is the number of ways one can select 3 items from 6.  It si 6!/3!/3!, or 6*5*4*3!/3!3!
2 blue and 1 red.  That is 6C2*8=120 ways and the total is 140 ways.