Question 87557
Assuming that this is what you mean: 

{{{((5t^3)/(4t-8)) * ((6t-12)/(10t)) }}} 

Factor the denominator of the first fraction and the numerator of the second fraction:

{{{((5t^3)/(4(t-2))) * ((6(t-2))/(10t)) }}}


Divide out the factors of (t-2):
{{{((5t^3)/4) * (6/(10t)) }}}


When you multiply, this leaves:
{{{(30t^3)/(40t)}}}


Reduce the fraction, by dividing out the 10 and t, which leaves factors of 3 and t^2 in the numerator, and a factor of 4 in the denominator.


{{{(3t^2)/4}}}


R^2  Retired from SCC