Question 1018726
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an isosceles right triangle is inscribed in a circle.
Find the radius of the circle if one leg of the triangle is 8 cm.
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Any right-angled triangle inscribed into the circle has the diameter as the hypotenuse.


Therefore, in our case the diameter of the circle is {{{sqrt(8^2 + 8^2)}}} = {{{sqrt(128)}}} = {{{8*sqrt(2)}}} cm.


Hence, the radius is half of that, i.e. {{{4*sqrt(2)}}} cm.