Question 87558
66x^2+67x+10=0using the quadratic equation we get:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
x=(-67+-sqrt[67^2-4*66*10])/2*66
x=(-67+-sqrt[4489-2640])/132
x=(-67+-sqrt[1849])/132
x=(-67+-43)/132
x=(-67+43)/132
x=24/132
x=.18181818 answer.
x=(-67-43)/132
x=110/132
x=.833333 answer.