Question 1018609
Question: Find two consecutive integers such that the larger is nine more than twice the smaller.

Answer: 

Let x be your first integer.
Then x + 1 will be the next consecutive integer.

Create the equation given in the original problem...

(x+1) = 2x + 9

Solve for x...

x + 1 = 2x + 9
1 = x + 9
x = -8

If x = -8, then (x+1) = -7.

Therefore the two consecutive integers you are looking for are -8 and -7.