Question 1018613
2x^2+8x-7=-2 
2x^2+8x-5=0
x=(1/4)*(-8+/- sqrt(64+40)=(1/4)*(-8+/-2 sqrt (26))=-2+/-(1/2)sqrt(26).
Numerically, this is about -4.55 and 0.55
{{{graph(300,200,-10,10,-10,10,2x^2+8x-5)}}}