Question 1018492
Knowing something about how an equation for parabola is derived is helpful.


An easy transformation of the equation is  {{{6(x-1/2)=y^2}}}.  Your parabola has a vertex at the left and parabola opens toward the right.  The vertex is  (1/2,0).


Comparing to a more generally derived equation, you could have {{{4p(x-1/2)=y^2}}} for p being distance from vertex to focus, so here, you have {{{p=3/2}}}.  You will expect the focus to be to the right of the vertex, for your example, and so the focus point is  (2,0).


(Latus Rectum is related to where the y values are in relation to the focus.)
(What are the y values for x=2 ?)