Question 1018244
.
A tour bus is traveling along a triangular path. The three straight lines
form a right triangle. One leg of the triangle represents a distance of 48
miles. The other leg of the triangle is 32 miles shorter than the
hypotenuse. What is the length of the hypotenuse of this triangle? Of the
other leg?
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<pre>
Solve the equation

{{{48^2 + (x-32)^2}}} = {{{x^2}}},

where x is the length of the hypotenuse.

{{{48^2 + x^2 - 64x + 32^2}}} = {{{x^2}}},

{{{64x}}} = {{{48^2 + 32^2}}},

x = {{{(48/8)^2 + (32/8)^2}}} = {{{6^2 + 4^2}}} = 36 + 16 = 52.

<U>Answer</U>. Hypotenuse is 52 miles. The other leg is 52 - 32 = 20 miles. 

        (It is a (5,12,13)-right-angled triangle).
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