Question 87511
Let e= a+bi, and e(complememt) = a-bi


What you have is 
e + 6ē = 7 
a+bi + 6(a-bi) = 7 +0i
a+bi +6a -6bi = 7 + 0i
7a -5bi = 6 + 0i


Therefore, 7a= 6, so a=6/7
and -5b= 0, so b=0


Therefore, e=6/7 +0i


R^2  Retired from SCC