Question 87511
Given that “e” is a complex number, solve e + 6ē = 7 (note: ē is the complex conjugate of e) 
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If e is a complex number, e = a + bi
If e-bar is its conjugate, e-bar = a-bi
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Substituting:
a+bi + 6(a-bi) = 7
7a -5bi =7 + 0i
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7a = 7, so a = 1
-5b = 0, so b = 0
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So e = 1 + 0i 
e = 1
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Cheers,
stan H.