<PRE><B>Question 1018079</B>
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ABCDEFGH is a regular octagon and AB=p and BC=q. Express AH in terms of p and q and show that AE+BH+CG+DF=2(2+&amp;#8730;2)(q-V2  times p).
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Your condition looks strange.


If ABCDEFGH is a regular octagon, then AB = p = BC = q = AH, as AB, BC and AH are the sides of the regular octagon.


Your comments?


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