Question 1018176
The width of a rectangle is 6 less than twice its length. If the area of the rectangle is 24 cm^2, what is the length of the diagonal? 
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length = "x"
width = "2x-6"
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Equation:
x(2x-6) = 24
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2x^2 - 6x - 24 = 0
x^2-3x-12 = 0
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x = [3+-sqrt(9-4*-12)]/2
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x = length = [3+-sqrt(57)]/2
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width = 2[length]-6
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diagonal = sqrt[length^2 + width^2]
Cheers,
Stan H.
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