Question 1018082
your equations are:


y = x^2 - 5x - 4
y = -2x


these are two equations that need to be solved simultaneously.


in the first equation, replace y with -2x from the second equation to get:


-2x = x^2 - 5x - 4


add 2x to both sides of this equation to get:


0 = x^2 - 5x - 4 + 2x


combine like terms to get 0 = x^2 - 3x - 4


this is the same as x^2 - 3x - 4 = 0


this is a quadratic equation in standard form.


factor the quadratic to get (x-4) * (x+1) = 0


solve for x to get x = 4 or x = -1.


go back to your original equations and solve for y.


you should get the same value of y for both equations.


when x = 4,y = -x b3comes y = -2*4 which becomes -8.


when x = -1, y = -2x becomes y = -2*-1 which becomes y = 2.


your coordinate points are (4,-8) and (-1,2).


since the leftmost point is x = -1, then you list your solutions as:


(-1,2) and (4,-8).


the graph of both your equations is shown below.


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