Question 1017852

The sum of the ages of Ron and Iezus is 92. In 6 years, the difference of their ages is 24. Given that Ron is older than Iezus, how old is each now?
<pre>Let Ron's age be R, and Iezus', I
Then: <b>R + I = 92 -------- eq (i)</b>
Once their ages differ by 24, it doesn't matter which year they're in, their ages will
always differ by 24, and since Ron is older, we get: <b>R = 24 + I --------- eq (ii)</b>
<b>24 + I + I = 92 --------- Substituting 24 + I for R in (i)</b>
        <b>2I = 92 - 24</b>
        2I = 68
I, or Iezus' age = {{{68/2}}}, or {{{highlight_green(34)}}}

<b>R = 24 + 34 --------- Substituting 34 for I in eq (ii)</b> 
R, or Ron's age = {{{highlight_green(58)}}}