Question 1017803
.
log(18-2x)=1

Solve the equation?
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<pre>
{{{log((18-2x))}}} = {{{1}}}  <----->  18 - 2x = 10   (I assume that the logarithm base is 10)  ----->  2x = 18 - 10 = 8  ---->  x = {{{8/2}}} = 4.


<U>Answer</U>.  x = 4.
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