<PRE><B>Question 1017708</B>
Kelly, a chemist, was asked to prepare 24 gallons of a solution that is 50% acidic by mixing a solution that is 20% acidic with another solution that is 70% acidic. How much of each solution should she use? 
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Equation::
acid + acid = acid
0.20x + 0.70(24-x) = 0.50*24
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20x + 70*24 - 70x = 50*24
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-50x = -20*24
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x = (2/5)*24
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x = 48/5 = 9.6 gallons (amt. of 20% solution needed)
24-x = 13.4 gallons (amt. of 70% solution needed)
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Cheers,
Stan H.
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