Question 1017609
Two planes which are 2475 miles apart fly toward each other. Their speed differ by 75mph. If they pass each other in 3 hours, what is the speed of each? 

I solved this and got: 
1st plane- 400mph
2nd plane- 475mph. 

Am I correct? 
================
Close.
The sum of the speeds is 2475/3 = 825 mi/hr
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F + S = 825
F - S = 75
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2F = 900
F = 450 mi/hr for the Faster plane.
--> 375 for the Slower.