<PRE><B>Question 1017542</B>
A train leaves New Orleans at 2:00 PM. A second train leaves the same city in the same direction at 4:00 PM. The second train travels 42 mph faster than the first. If the second train overtakes the first at 6:00 PM, what is the speed of each of the two trains?
let x=speed of slower train
travel time of slower train=6-2=4 hrs
x+42=speed of faster train
distance=speed*travel time(same for both trains)
travel time of faster train=6-4=2 hrs
 4x=2(x+42) 
4x=2x+84
2x=84
x=42
x+42=84  
speed of slower train= 84 mph
speed of faster train=42 mph </PRE>