Question 1017401
Let {{{ s }}} = the speed of the bicycle in mi/hr
{{{ s + 36.8 }}} = the speed of the car in mi/hr
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You can think of one of them moving at the sum
of their speeds and the other one standing still,
because they are moving towards eachother.
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The distance traveled will be the sum of the
distances each would have traveled
in {{{ 5.5 }}} hrs
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{{{ 308 = ( s + s + 36.8 )*5.5 }}}
{{{ 308 = 2s*5.5 + 36.8*5.5 }}}
{{{ 308 = 11s + 202.4 }}}
{{{ 11s = 105.6 }}}
{{{ s = 9.6 }}}
and
{{{ s + 36.8 = 9.6 + 36.8 }}}
{{{ s + 36.8 = 46.4 }}}
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The speed of the bicycle is 9.6 mi/hr
The speed of the car is 46.4 mi/hr
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check answers:
For the bicycle:
{{{ d[1] = 9.6*5.5 }}}
{{{ d[1] = 52.8 }}}
For the car:
{{{ d[2] = 46.4*5.5 }}}
{{{ d[2] = 255.2 }}}
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{{{ d = d[1] + d[2] }}}
{{{ d = 52.8 + 255.2 }}}
{{{ d = 308 }}}
OK