Question 1017389
The volume of ice needed is the area of the rink times the depth, 0.1 m.
The rink is a 60m by 30m rectangle.  That area is 1800 m^2.
The semi-circles at each end become a full circle whose radius is 15m
Its area is A = (pi)r^2 = (3.14)(15^2) = 706.5 m^2
Thus the total area of the rink is
1800 + 706.5 = 2506.5 m
Now multiply that by the depth (0.1m) and we get
V = 2506.5 * 0.1 = 250.65 cubic meters of ice.