Question 1017292
Find the perimeter of the triangle with the vertices at 

(1, 2), (-6, 5), and (-6, -4). 
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Use the distance formula to find the 3 side lengths.
Perimeter = the sum of the 3 lengths.
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A(1,2), B(-6,5), and C(-6,-4)
{{{AB = sqrt(diffy^2 + diffx^2) = sqrt(3^2 + 7^2) = sqrt(58)}}}