Question 1017338
Find sum of first 100 terms of an arithmetic 
sequence with 15th term of 86 and first term of 2. 
<pre><b>
a<sub>n</sub> = a<sub>1</sub> + (n-1)d

86 = 2 + (15-1)d

84 = 14d

{{{84/14}}} = d 

6 = d

S<sub>n</sub> = {{{n/2}}}[2a<sub>1</sub> + (n-1)d] 


S<sub>100</sub> = {{{100/2}}}[2(2) + (100-1)6]

S<sub>100</sub> = 50[4 + (99)6]

S<sub>100</sub> = 50[4 + 594]

S<sub>100</sub> = 50[598]

S<sub>100</sub> = 29900

Edwin</pre></b>