Question 1017288
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One pump can fill a gasoline storage in 8 hours. With a second pump working simultaneously, the tank can be filled in 3 hours. 
How long would it take the second pump to fill the the tank alone? 
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The rate of the first pump is {{{1/8}}} of the tank volume per hour.

The rate of the two pipes, when they work simultaneously, is {{{1/3}}} of the tank volume per hour.

Hence, the rate of the second pipe, when it works alone, is 

{{{1/3}}} - {{{1/8}}} = {{{8/24}}} - {{{3/24}}} = {{{(8-3)/24}}} = {{{5/24}}}

of the tank volume per hour.

It means that it takes {{{24/5}}} of an hour for the second pipe to fill the tank if it works alone.

{{{24/5}}} hours = 4 hours and 48 minutes.
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