Question 1017157
.
 If 4 + I and 4 - I are roots of the equation z^2 + az + b = 0 find the value of a and the value of b?
--------------------------------------------


<pre>
Since the quadratic equation has the coefficient "1" as the leading coefficient (at {{{z^2}}}), then 

z1 + z2 = -a,
Z1*z2 = b.

Hence, a = (4+i)*(4-i) = 16 - {{{i^2}}} = 16 - (-1) = 16 + 1 = 17.

       b = (4+i) + (4-i) = 8.

That is all.
</pre>