Question 1017095
 In the morning, Maria drove to a business appointment at 60mph.
 Her average speed on the return trip in the afternoon was 50mph.
 The return trip took 1/5 hr longer because of heavy traffic.
 How far did she travel to the appointment? 
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let d = one-way distance
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Write a time equation; time = dist/speed
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"The return trip took 1/5 hr longer because of heavy traffic."
1/5 = .2 hr
return time = "to" time + .2 hrs
{{{d/50}}} = ({{{d/60}}}) + .2
multiply equation by 300, cancel the denominators and you have
6d = 5d + 300(.2)
6d - 5d = 60
d = 60 mi one-way. Total travel dist = 120 mi 
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Confirm this, find the actual time each way
60/50 = 1.2 hrs
60/60 = 1 hr