Question 1017103
When the number 2205 is divided by a 2-digit number, the remainder is 21, find the possible values of the 2 digit number. 
----

2205 = k(10t+u) + 21
k(10t+u) = 2184
k = 2184/(10t+u)
---
Solve y = 2184/x for x being a 2-digit number and y being a natural number.
---
Use your calculator to find the whole number answers for "y"::
Ans: x = 12, or 13 or 14, or 21 or 24 or 26 etc.
--
Cheers,
Stan H.