Question 1016913
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Please help me know what the completely factored form of:   
k^4-4k^2+8K^3-32k+12k^2-48
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<pre>
{{{k^4 - 4k^2 + 8K^3 - 32k + 12k^2 - 48}}} =                 <---  make grouping

= {{{(k^4 - 4k^2)}}} + {{{(8K^3 - 32k)}}} + {{{(12k^2 - 48)}}} =    <--- take the common factors out of parentheses

= {{{k^2*(k^2 - 4)}}} + {{{8k*(k^2 - 4)}}} + {{{12*(k^2 - 4)}}} =

= {{{(k^2 + 8k + 12)*(k^2-4)}}}.
</pre>