Question 1017052
For (A), P = J + 10
To solve (B):
P = J + 10
(5x-4) = (2x+1) + 10
5x - 4 = 2x + 11
Subtract 2x from each side, and add 4 to each side
3x = 15
Divide by 3
x = 5
Therefore, Peter is 5(5) - 4, or 21.  John is 2(5)+1, or 11.
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