Question 1017028
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{{{(5-4i)/(8+6i)}}}
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{{{((5-4i)/(8+6i))((8-6i)/(8-6i))}}}={{{((5-4i)(8-6i))/(64+36)}}}={{{(40-30i-32i+24i^2)/100=(40-62i-24)/100}}}={{{(16-62i)/100=(8-31i)/50}}}