Question 1016893
the word is educated.


without any duplicates the number of permutations would be 8! because there are 8 letters.


since 2 of the letters are duplicates, the formula becomes 8! / (2! * 2!) = 8! / 4


since 8! = 8*7*6*5*4*3*2*1, then 8! = 40320


8! / 4 becomes 40320 / 4 = 10080.


here's a good reference.


<a href = "http://www.regentsprep.org/regents/math/algebra/apr2/LpermRep.htm" target = "_blank">http://www.regentsprep.org/regents/math/algebra/apr2/LpermRep.htm</a>