Question 1016883
 
Question:
Evaluate Log8base4+log2base4
 
Solution:
We will need basic definition of log x to the base b, and some laws of logarithms:
y=log<sub>b</sub>x   means  b<sup>y</sup>=x
hence
log<sub>b</sub>b=1
and
log(a)+log(b)=log(ab)
log(a&sup2;)=2log(a)
 
log<sub>4</sub>(8)+log<sub>4</sub>(2)
=log<sub>4</sub>(8*2)
=log<sub>4</sub>(16)
=log<sub>4</sub>(4^2)
=2log<sub>4</sub>(4)
=2*1
=2