Question 87358
x^2 + y^2 + 2x + 4y - 9 = 0
x^2 + 2x + y^2 + 4y  = 9
(x^2 + 2x) + (y^2 + 4y) = 9
(x + 1)^2 - 1 + (y + 2)^2 - 4 = 9
(x + 1)^2 + (y + 2)^2 = 14
C(-1,-2)
{{{graph(300,300,-7,5,-7,5,sqrt(14 - (x + 1)^2) - 2,-sqrt(14 - (x + 1)^2) - 2)}}}