Question 1016696
The sum of the ages of Luis and Shannon is 108 years. 9 years ago, Luis's age was 4 times Shannon's age. How old is Luis now?
<pre>Let Luis' age, be L
Then Shannon's is: 108 - L
We then get: L - 9 = 4(108 - L - 9)			
L - 9 = 4(99 - L)
L - 9 = 396 - 4L 
L + 4L = 396 + 9
5L = 405
L, or Luis' current age = {{{405/5}}}, or {{{highlight(highlight_green(highlight(81)))}}}