<PRE><B>Question 1016712</B>
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A rectangular field has the dimensions of 70m×60m. A well is dug outside this field and its measures are 14m×5m×5m. 
The soil taken out of the well is evenly spread on the field. What is the height of the newly spread soil?
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It is {{{(14*5*5)/(70*60)}}} = 0.08333... m = 8.3 cm.


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