Question 1016508
Is this supposed to be {{{m[n] = (1/2)*(m[n-1]-1)}}}?

{{{m[1] = 13}}}

{{{m[2] = (1/2)*(m[1]-1) = (1/2)*(13-1) = 6}}}

{{{m[3] = (1/2)*(m[2]-1) = (1/2)*(6-1) = 5/2}}}

{{{m[4] = (1/2)*(m[3]-1) = (1/2)*(5/2-1) = 3/4}}}

{{{m[5] = (1/2)*(m[4]-1) = (1/2)*(3/4-1) = -1/8}}}

In general,the general formula would be {{{m[n] = 14/2^(n-1) -1}}} for n = 1, 2, 3, 4, 5,...