Question 1016558
*[tex \large f\left(\frac{x-3}{x+1}\right) + f\left(\frac{x+3}{1-x}\right) = x] for all x other than 1, -1.


If x = 0, then *[tex \large f(-3) + f(3) = 0]
If x = 3, then *[tex \large f(0) + f(-3) = 3]
If x = -3, then *[tex \large f(3) + f(0) = -3]


These three statements imply *[tex \large f(0) = 0], *[tex \large f(3) = -3], and *[tex \large f(-3) = 3]. However I could not determine anymore useful information about f(x). Where is this problem from?