Question 1016498
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What are all the possible values for x using the pythagorean theorum of a right triangle when the hypotenuse is 27 and one leg is (2x+5)
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The second leg is {{{sqrt(27^2 - (2x+5)^2)}}}.


The only restriction for x is this inequality:

2x + 5 < 27,  

which says that the leg is shorter than the hypotenuse.

The last inequality means that x < 11.
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