Question 1016482
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divde (x/3+1/6)/(1/2+1/3)
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<pre>
{{{(x/3+1/6)/(1/2+1/3)}}} = 


First write the fractions in the numerator {{{x/3 + 1/6}}} with common denominator:

{{{x/3 + 1/6}}} = {{{2x/6 + 1/6}}} = {{{(2x+1)/6}}}.


Next write fractions in the denominator {{{1/2 + 1/3}}} with common denominator:

{{{1/2 + 1/3}}} = {{{3/6 + 2/6}}} = {{{5/6}}}.


Now your expression is 

{{{(((2x+1)/6))/((5/6))}}} = {{{(2x+1)/5}}}.
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