<PRE><B>Question 1016356</B>
An east bound car is observed 2 miles north of an outpost 10 minutes later its bearing is 80° 45&#39; east.
 Find the speed of the car in mph 
:
Change 80 degrees 45 min to 80.75 degrees
This can be solved as a right triangle.
 The car travels at a right angle from a 2 mi line from the observer.
 The distance (d) traveled by the car is the side opposite 80.75 degrees 
Tan(80.75) = {{{d/2}}}
d = 6.14023 * 2
d = 12.28 mi, it traveled in 10 min
:
10 min is 1/6 of an hr. Speed = dist/time
S = {{{12.28/(1/6)}}}
S = 12.28 * 6
S = 73.68 mph</PRE>