Question 1016261
Ed has 95 cents in dimes and nickels. The total number of coins is one more than twice the number of dimes. How many dimes does she have?
I'm confused on this because it doesn't doesn't tell me a total number so I'm
Not sure what to go off of
The only equation I could think of was
.10d + .05n = .95 
:
Write an equation for the statement
"the total number of coins is one more than twice the number of dimes."
d + n = 2d + 1
n = 2d - d + 1
n = d + 1
now, in your first equation you can substitute (d+1) for n

.10d + .05(d+1) = .95
.10d + .05d + .05 = .95
.15d = .95 - .05
.15d = .90
d = .90/.15
d = 6 dimes
I'll let you find the no. of nickels, check your solutions in the 1st equation