Question 1016003
If {{{y[1]=5/(x+4)}}} , {{{y[2]=4/(x+2)}}} , and {{{y[3]=(11x+22)/(x^2+6x+8)}}} ,
there is no value of {{{x}}} that will make {{{y[1]=y[2]=y[3]}}} .
{{{y[3]=(11x+22)/(x^2+6x+8)=11(x+2)/((x+4)(x+2))}}}
is undefined for {{{x=-2}}} or {{{x=-4}}} .
For all other values,
{{{y[3]=11/(x+4)}}} and {{{y[3]=11/(x+4)<>5/(x+4)=y[1]}}}