Question 1016158
Parallel line would have the same structure.
{{{-2x+4y=D}}}
The y-intercept of the second equation is,
{{{4(0)-3y=0}}}
{{{y=0}}}
(0,0)
So then finding {{{D}}},
{{{-2(0)+4(0)=D}}}
{{{D=0}}}
{{{-2x+4y=0}}}
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