Question 87297
Lets find the equation of the line through the two points (1,4) and (3,10)


*[invoke calculating_slope 1, 4, 3, 10]


Now lets plot the point (2,7) and {{{y=3x+1}}}



{{{ drawing( 500, 500, -10, 10, -10, 10,
graph( 500, 500, -10, 10, -10, 10, 3x+1)
circle(2,7,0.08),
circle(2,7,0.1)
) }}} graph of {{{y=3x+1}}} with the point (2,7)


Since the point is on the line, the equation of the line that goes through (1,4),(2,7),and(3,10) is {{{y=3x+1}}}


Now lets pick any other x value so we can plot another point. Let x=0


{{{3(0)+1=0+1=1}}} plug in {{{x=0}}}


So we have another point (0,1)


So we have this graph and these points


{{{ drawing( 500, 500, -10, 10, -10, 10,
graph( 500, 500, -10, 10, -10, 10, 3x+1)
circle(2,7,0.08),
circle(2,7,0.1),
circle(0,1,0.08),
circle(0,1,0.1),
circle(1,4,0.08),
circle(1,4,0.1),
circle(3,10,0.08),
circle(3,10,0.1)
) }}} graph of {{{y=3x+1}}} with the points (0,1),(1,4),(2,7), and (3,10)