Question 1015666
{{{H[o]}}}:{{{mu<=7}}}
{{{H[a]}}}:{{{mu>7}}}
From the data, the mean is 7.033.
{{{s/sqrt(n)=1.376736/sqrt(30)=0.251356}}}
Calculating the t score from this information,
{{{t=(7.033-7)/0.251356=0.1326}}}
The critical t value for a one tailed test with 29 DOFs would be 
{{{t[CR]=1.699}}}
Since {{{t<t[CR]}}}, you don't have enough evidence to reject the null hypothesis.