Question 1015880
ln(x+2)-1
x must be greater than -2.
As x approaches -2, ln (x+2) gets more and more negative, so x=-2 is vertical asymptote.                                                                        When x=0, y=ln(2)-1, =-0.3
when y=0,
ln(x+2)=1 and raising both to the e power, (x+2)=2.7 and x=0.7
ln(1)=0, therefore x=-1, y=-1
Table
0,-0.3
0.7,0
-1,-1
{{{graph(300,200,-3,2,-5,1,ln(x+2)-1)}}}