<PRE><B>Question 1015898</B>
pure antifreeze=x qts.
(6+x)*0.40=6*0.20+x
2.40+0.40x=1.2+x
1.20=0.6x
x=2 qts.
What you want to equalize is the amount of pure antifreeze in both sides of the equation.
you start with 1.2 (6*0.2) qts.
you are adding x qts to 6.
you are ending up with (6+x) qts of 40% or 0.4
8 qts of 0.4=3.2 qts of pure
You start with 6 qts. and end up with 8.
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