Question 1014080
We have *[tex \large \frac{1}{3} \times A \times 2 = 10] where A is the area of the base (in m^2), so A = 15 m^2.


Using the area of an equilateral triangle, we have *[tex \large \frac{s^2 \sqrt{3}}{4} = 15]. Solving, *[tex \large s^2 = 20 \sqrt{3}] or *[tex \large s = \sqrt{20 \sqrt{3}}].