Question 87268

    let the amount invested at 9% be = x interest =9x/100
        amount invested at 11%=(6000-x)  interest =(6000-x).11/100
       total interest = 624 hence 9x/100+(6000-x).11/100=624
              9x/100-11x/100+660=624   -2x/100=624-660 
                                      -2x/100=-36    or x=1800  6000-1800=4200
          amount invested at 9% interest=Rs1800
          amount invested at 11%interest=Rs 4200