Question 1015675
f(x) = x +3
g(x) = √(x-1)
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A) (f+g)(x) = x+3 + √(x-1)
for x = 1,
(f+g)(1) = 1+3 +0 = 4
:
(f-g)(x) = x +3 -√(x-1)
for x = 1
(f-g)(x) = 1 +3 -0 = 4
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B) Domain f(x) is all real numbers
Domain of g(x) is all real numbers > 1, since any real number less than 1 causes us to take the square root of a negative number which is an imaginary number
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C) we know g(1) = 0, therefore
(f+g(1)(x) = f(x)
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